{"id":441,"date":"2014-12-12T16:02:07","date_gmt":"2014-12-12T16:02:07","guid":{"rendered":"http:\/\/www.studyorgo.com\/blog\/?p=441"},"modified":"2014-12-12T16:02:07","modified_gmt":"2014-12-12T16:02:07","slug":"acetal-formation","status":"publish","type":"post","link":"https:\/\/www.studyorgo.com\/blog\/acetal-formation\/","title":{"rendered":"Acetal Formation"},"content":{"rendered":"<p><strong>Intermolecular Acid-Catalyzed Acetal Formation<\/strong><\/p>\n<p><strong>Ketone + diol\u00a0\u2192 Acetal<\/strong><\/p>\n<p><strong>Overall Big Picture:<\/strong>\u00a0This reaction forms a hemiacetal from an aldehyde or ketone and a diol and further reacts to form the acetal group.<\/p>\n<p><strong>Key Tip:<\/strong>\u00a0In the presence of alcohols under acidic conditions, carbonyls can be reduced to acetals.<\/p>\n<p>Full reaction description including our proven flash card method and mechanism is available for members only. \u00a0<a href=\"\/signup.php\">Join here&#8230;<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Intermolecular Acid-Catalyzed Acetal Formation Ketone + diol\u00a0\u2192 Acetal Overall Big Picture:\u00a0This reaction forms a hemiacetal from an aldehyde or ketone and a diol and further reacts to form the acetal group. Key Tip:\u00a0In the presence of alcohols under acidic conditions, carbonyls can be reduced to acetals. Full reaction description including our proven flash card method [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":442,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[16,15],"tags":[],"class_list":["post-441","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-aldehydes-and-ketones","category-organic-chemistry-reactions"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/posts\/441","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/comments?post=441"}],"version-history":[{"count":1,"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/posts\/441\/revisions"}],"predecessor-version":[{"id":443,"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/posts\/441\/revisions\/443"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/media\/442"}],"wp:attachment":[{"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/media?parent=441"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/categories?post=441"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.studyorgo.com\/blog\/wp-json\/wp\/v2\/tags?post=441"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}